A vector bundle over a scheme
is a scheme with a projection map
in which locally is has the form
, i.e there is an isomorphism over
. The local descriptions have to be compatible in the following sense :
if we have an overlapping then
induces a map of
into inself, the dual of which is required to be linear ( i.e., if
is the ring of section on
, then the dual map of
into itself is a linear isomorphism on the variables
).
Then we have the following properties :
- To give a vector bundle over
is the same as to give the associated sheaf of its section, which is locally free of rank
. To see this, note that to give a section over
is the same as to give an
-algebra-morphism from
to
, this is the same as to give
elements in
, i.e, an element of
. Now we need to see what happen at overlaps
. We have an automorphism
to itself, and two linear morphisms (on variables
) to
, which both send
to a basis. Then the two linear morphisms extend to corresponding isomorphisms of
algebras to the symmetric power of
. Now the transition functions for locally free sheaf are linear, hence the linear automorphisms of
will force
to be linear.
- is the cone over
with the corresponding sheaf of
is the symmetric algebra of the dual of its sheaf of section (*).
To see why (*) is true, note that if we denote to be the sheaf of sections, then on each open set
where it is trivial,
can be identified with the linear map from
to
, hence its dual sheaf is
itself and hence if we take the symmetric algebra of this sheaf we recover the structure sheaf
on each open set
of the vector bundle.
- To give a homomorphism of vector bundles is the same as to a morphism
of the sheaves of sections, as can be seen by composing a section of
with
we get a section of
. Hence to give such homomorphism is the same as to give a section of the bundle
Thus, a vector bundle can be identify with its sheaf of sections, although its structure sheaf comes from taking the symmetric algebra of the dual sheaf of its sheaf of sections.