Vector bundle and its sheaf of sections

May 6, 2008 by dunghoangnguyen

A vector bundle E over a scheme X is a scheme with a projection map \pi:  E  \to X in which locally is has the form U \times A^n \to U, i.e there is an isomorphism over U , \phi_U :  \pi^{-1}(U) \cong U \times A_{\mathbb{Z}}^n . The local descriptions have to be compatible in the following sense :

if we have an overlapping U \cap V then \phi_V^-1 \circ \phi_U induces a map of U \cap V \times A^n into inself, the dual of which is required to be linear ( i.e., if R is the ring of section on U \cap V , then the dual map of R[x_1,\ldots x_n] into itself is a linear isomorphism on the variables x_i).

Then we have the following properties :

- To give a vector bundle E over X is the same as to give the associated sheaf of its section, which is locally free of rank n. To see this, note that to give a section over U is the same as to give an O_U-algebra-morphism from O_U[x_1,\ldots,x_n] to O_U, this is the same as to give n elements in O_U, i.e, an element of O_U^{\oplus n} . Now we need to see what happen at overlaps U \cap V. We have an automorphism a : O_{U\cap V}[x_1,\ldots,x_n] to itself, and two linear morphisms (on variables x_i) to O_{U \cap V}^{\oplus n} , which both send x_i to a basis. Then the two linear morphisms extend to corresponding isomorphisms of O_{U\cap V} algebras to the symmetric power of O_{U \cap V}^{\oplus n} . Now the transition functions for locally free sheaf are linear, hence the linear automorphisms of O_{U \cap V}^{\oplus n} will force f to be linear.

- E is the cone over X with the corresponding sheaf of O_X is the symmetric algebra of the dual of its sheaf of section (*).

To see why (*) is true, note that if we denote \epsilon to be the sheaf of sections, then on each open set U where it is trivial, \epsilon(U) can be identified with the linear map from O_U[x_1] \oplus \cdots \oplus O_U[x_n] to O_U, hence its dual sheaf is O_U[x_1] \oplus \cdots \oplus O_U[x_n] itself and hence if we take the symmetric algebra of this sheaf we recover the structure sheaf O_U[x_1,\ldots,x_n] on each open set U of the vector bundle.

- To give a homomorphism f: E \to F of vector bundles is the same as to a morphism E g of the sheaves of sections, as can be seen by composing a section of E with f we get a section of F . Hence to give such homomorphism is the same as to give a section of the bundle Hom(E,F) = Hom(\epsilon, \eta) = \check{\epsilon} \otimes \eta = \check{E} \otimes F

Thus, a vector bundle can be identify with its sheaf of sections, although its structure sheaf comes from taking the symmetric algebra of the dual sheaf of its sheaf of sections.

Projective completion of a cone over a scheme

May 6, 2008 by dunghoangnguyen

A cone C over a scheme X is the Spec of the sheaf of graded O_X- algebra S = S_0 \oplus S_1 \oplus \ldots , S is generated by S_1 as an S_0 \cong O_X algebra.

The projective completion is Proj(S[z]= T) where we give the variable z grade 1. Then z is a global section of the canonical O(1) on the projective completion, the zero scheme of which is precisely Proj S, and whose complement is exactly C ( Check on local base : if we localize at f \in T_1, then \{ z=0 \} \cong Proj S_f, and \{ z \neq 0 \} \cong Spec S_f via the isomorphism of S_0- algebras sending each h \in A_1 to h/z)

What is this weblog about?

April 23, 2008 by dunghoangnguyen

This weblog is intended to be the place where I discuss about mathematics. My interests are Intersection Theory , Elliptic Curves, Algebraic Topology, Knots, and Graph Theory.